Base | Representation |
---|---|
bin | 11110101101000111000… |
… | …011010101111110010111 |
3 | 21110201022222202210110002 |
4 | 132231013003111332113 |
5 | 234032310334013421 |
6 | 4253155200521515 |
7 | 305305200404162 |
oct | 36550703257627 |
9 | 7421288683402 |
10 | 2110021001111 |
11 | 743944935391 |
12 | 2a0b2992029b |
13 | 123c8820526a |
14 | 741a877cad9 |
15 | 39d46d72b0b |
hex | 1eb470d5f97 |
2110021001111 has 2 divisors, whose sum is σ = 2110021001112. Its totient is φ = 2110021001110.
The previous prime is 2110021001087. The next prime is 2110021001113. The reversal of 2110021001111 is 1111001200112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2110021001111 - 26 = 2110021001047 is a prime.
Together with 2110021001113, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2110021001092 and 2110021001101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110021001113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055010500555 + 1055010500556.
It is an arithmetic number, because the mean of its divisors is an integer number (1055010500556).
Almost surely, 22110021001111 is an apocalyptic number.
2110021001111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110021001111 is an equidigital number, since it uses as much as digits as its factorization.
2110021001111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 2110021001111 its reverse (1111001200112), we get a palindrome (3221022201223).
The spelling of 2110021001111 in words is "two trillion, one hundred ten billion, twenty-one million, one thousand, one hundred eleven".
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