Base | Representation |
---|---|
bin | 11110101101010001110… |
… | …101111000000100001111 |
3 | 21110201210121101111211111 |
4 | 132231101311320010033 |
5 | 234033143204120421 |
6 | 4253225144432451 |
7 | 305312526135313 |
oct | 36552165700417 |
9 | 7421717344744 |
10 | 2110202020111 |
11 | 743a28033669 |
12 | 2a0b7a478727 |
13 | 123cb6874bb3 |
14 | 741c481db43 |
15 | 39d57bccee1 |
hex | 1eb51d7810f |
2110202020111 has 2 divisors, whose sum is σ = 2110202020112. Its totient is φ = 2110202020110.
The previous prime is 2110202020109. The next prime is 2110202020133. The reversal of 2110202020111 is 1110202020112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2110202020111 - 21 = 2110202020109 is a prime.
Together with 2110202020109, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 2110202020091 and 2110202020100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110202720111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055101010055 + 1055101010056.
It is an arithmetic number, because the mean of its divisors is an integer number (1055101010056).
Almost surely, 22110202020111 is an apocalyptic number.
2110202020111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110202020111 is an equidigital number, since it uses as much as digits as its factorization.
2110202020111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2110202020111 its reverse (1110202020112), we get a palindrome (3220404040223).
Subtracting from 2110202020111 its reverse (1110202020112), we obtain a palindrome (999999999999).
The spelling of 2110202020111 in words is "two trillion, one hundred ten billion, two hundred two million, twenty thousand, one hundred eleven".
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