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211021220213 is a prime number
BaseRepresentation
bin1100010010000111011…
…0000100100101110101
3202011200102122200101122
43010201312010211311
511424132413021323
6240535233033325
721150205530236
oct3044166044565
9664612580348
10211021220213
1181547a83061
1234a926b5845
1316b8c76645b
14a2dbb1708d
155750d05ec8
hex3121d84975

211021220213 has 2 divisors, whose sum is σ = 211021220214. Its totient is φ = 211021220212.

The previous prime is 211021220161. The next prime is 211021220227. The reversal of 211021220213 is 312022120112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 204165711409 + 6855508804 = 451847^2 + 82798^2 .

It is a cyclic number.

It is not a de Polignac number, because 211021220213 - 212 = 211021216117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 211021220191 and 211021220200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211021220413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105510610106 + 105510610107.

It is an arithmetic number, because the mean of its divisors is an integer number (105510610107).

Almost surely, 2211021220213 is an apocalyptic number.

It is an amenable number.

211021220213 is a deficient number, since it is larger than the sum of its proper divisors (1).

211021220213 is an equidigital number, since it uses as much as digits as its factorization.

211021220213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 211021220213 its reverse (312022120112), we get a palindrome (523043340325).

The spelling of 211021220213 in words is "two hundred eleven billion, twenty-one million, two hundred twenty thousand, two hundred thirteen".