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21104003124299 is a prime number
BaseRepresentation
bin1001100110001101010001…
…00111000000110001001011
32202201112010021010001120102
410303012220213000301023
510231231444244434144
6112515013432320015
74305466604524514
oct463065047006113
982645107101512
1021104003124299
1167a7180646617
12244a11bb4300b
13ba11395357c4
1452d62124da0b
15268e6bec7b4e
hex1331a89c0c4b

21104003124299 has 2 divisors, whose sum is σ = 21104003124300. Its totient is φ = 21104003124298.

The previous prime is 21104003124263. The next prime is 21104003124301. The reversal of 21104003124299 is 99242130040112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21104003124299 - 240 = 20004491496523 is a prime.

Together with 21104003124301, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21104003124209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10552001562149 + 10552001562150.

It is an arithmetic number, because the mean of its divisors is an integer number (10552001562150).

Almost surely, 221104003124299 is an apocalyptic number.

21104003124299 is a deficient number, since it is larger than the sum of its proper divisors (1).

21104003124299 is an equidigital number, since it uses as much as digits as its factorization.

21104003124299 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 21104003124299 in words is "twenty-one trillion, one hundred four billion, three million, one hundred twenty-four thousand, two hundred ninety-nine".