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21110020037 is a prime number
BaseRepresentation
bin10011101010010000…
…010101011111000101
32000111012020010110222
4103222100111133011
5321213131120122
613410420554125
71345061131631
oct235220253705
960435203428
1021110020037
118a53068557
124111852945
131cb5656322
1410438b1dc1
15838430b42
hex4ea4157c5

21110020037 has 2 divisors, whose sum is σ = 21110020038. Its totient is φ = 21110020036.

The previous prime is 21110020013. The next prime is 21110020039. The reversal of 21110020037 is 73002001112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10764892516 + 10345127521 = 103754^2 + 101711^2 .

It is a cyclic number.

It is not a de Polignac number, because 21110020037 - 214 = 21110003653 is a prime.

Together with 21110020039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21110019997 and 21110020024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21110020039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10555010018 + 10555010019.

It is an arithmetic number, because the mean of its divisors is an integer number (10555010019).

Almost surely, 221110020037 is an apocalyptic number.

It is an amenable number.

21110020037 is a deficient number, since it is larger than the sum of its proper divisors (1).

21110020037 is an equidigital number, since it uses as much as digits as its factorization.

21110020037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 17.

Adding to 21110020037 its reverse (73002001112), we get a palindrome (94112021149).

The spelling of 21110020037 in words is "twenty-one billion, one hundred ten million, twenty thousand, thirty-seven".