Base | Representation |
---|---|
bin | 11110101110000011010… |
… | …101001100010111010111 |
3 | 21110210221110201202222012 |
4 | 132232003111030113113 |
5 | 234041343233011203 |
6 | 4253443404454435 |
7 | 305342230411214 |
oct | 36560325142727 |
9 | 7423843652865 |
10 | 2111032313303 |
11 | 744313785191 |
12 | 2a117054a41b |
13 | 1240b98a3344 |
14 | 74262bd2b0b |
15 | 39da5a3abd8 |
hex | 1eb8354c5d7 |
2111032313303 has 2 divisors, whose sum is σ = 2111032313304. Its totient is φ = 2111032313302.
The previous prime is 2111032313263. The next prime is 2111032313353. The reversal of 2111032313303 is 3033132301112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111032313303 - 234 = 2093852444119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111032313353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055516156651 + 1055516156652.
It is an arithmetic number, because the mean of its divisors is an integer number (1055516156652).
Almost surely, 22111032313303 is an apocalyptic number.
2111032313303 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111032313303 is an equidigital number, since it uses as much as digits as its factorization.
2111032313303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 2111032313303 its reverse (3033132301112), we get a palindrome (5144164614415).
The spelling of 2111032313303 in words is "two trillion, one hundred eleven billion, thirty-two million, three hundred thirteen thousand, three hundred three".
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