Base | Representation |
---|---|
bin | 110000000000000011100000… |
… | …100111100100010111111111 |
3 | 1000200110220210221120121201101 |
4 | 300000003200213210113333 |
5 | 210132311240224030413 |
6 | 2024554332352153531 |
7 | 62316123424553626 |
oct | 6000034047442777 |
9 | 1020426727517641 |
10 | 211110001001983 |
11 | 612a2280a37156 |
12 | 1b8166482388a7 |
13 | 90a4784170c05 |
14 | 3a1bac85606bd |
15 | 19616c798cedd |
hex | c000e09e45ff |
211110001001983 has 2 divisors, whose sum is σ = 211110001001984. Its totient is φ = 211110001001982.
The previous prime is 211110001001959. The next prime is 211110001002007. The reversal of 211110001001983 is 389100100011112.
It is a balanced prime because it is at equal distance from previous prime (211110001001959) and next prime (211110001002007).
It is a cyclic number.
It is not a de Polignac number, because 211110001001983 - 241 = 208910977746431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211110001001923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555000500991 + 105555000500992.
It is an arithmetic number, because the mean of its divisors is an integer number (105555000500992).
Almost surely, 2211110001001983 is an apocalyptic number.
211110001001983 is a deficient number, since it is larger than the sum of its proper divisors (1).
211110001001983 is an equidigital number, since it uses as much as digits as its factorization.
211110001001983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 28.
The spelling of 211110001001983 in words is "two hundred eleven trillion, one hundred ten billion, one million, one thousand, nine hundred eighty-three".
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