Base | Representation |
---|---|
bin | 11110101110000111011… |
… | …111100000000001011001 |
3 | 21110211010100002112102001 |
4 | 132232013133200001121 |
5 | 234042014120432441 |
6 | 4253454341041001 |
7 | 305344035656254 |
oct | 36560737400131 |
9 | 7424110075361 |
10 | 2111102124121 |
11 | 74434a127081 |
12 | 2a118b9b6161 |
13 | 1240cb1a6a13 |
14 | 7426c1a609b |
15 | 39dabc2a731 |
hex | 1eb877e0059 |
2111102124121 has 2 divisors, whose sum is σ = 2111102124122. Its totient is φ = 2111102124120.
The previous prime is 2111102124083. The next prime is 2111102124127. The reversal of 2111102124121 is 1214212011112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2038644251721 + 72457872400 = 1427811^2 + 269180^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111102124121 - 213 = 2111102115929 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111102124127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055551062060 + 1055551062061.
It is an arithmetic number, because the mean of its divisors is an integer number (1055551062061).
Almost surely, 22111102124121 is an apocalyptic number.
It is an amenable number.
2111102124121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111102124121 is an equidigital number, since it uses as much as digits as its factorization.
2111102124121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 2111102124121 its reverse (1214212011112), we get a palindrome (3325314135233).
The spelling of 2111102124121 in words is "two trillion, one hundred eleven billion, one hundred two million, one hundred twenty-four thousand, one hundred twenty-one".
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