Base | Representation |
---|---|
bin | 11110101110000111011… |
… | …111100000000001011111 |
3 | 21110211010100002112102021 |
4 | 132232013133200001133 |
5 | 234042014120433002 |
6 | 4253454341041011 |
7 | 305344035656263 |
oct | 36560737400137 |
9 | 7424110075367 |
10 | 2111102124127 |
11 | 74434a127087 |
12 | 2a118b9b6167 |
13 | 1240cb1a6a19 |
14 | 7426c1a60a3 |
15 | 39dabc2a737 |
hex | 1eb877e005f |
2111102124127 has 2 divisors, whose sum is σ = 2111102124128. Its totient is φ = 2111102124126.
The previous prime is 2111102124121. The next prime is 2111102124139. The reversal of 2111102124127 is 7214212011112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111102124127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111102124121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055551062063 + 1055551062064.
It is an arithmetic number, because the mean of its divisors is an integer number (1055551062064).
Almost surely, 22111102124127 is an apocalyptic number.
2111102124127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111102124127 is an equidigital number, since it uses as much as digits as its factorization.
2111102124127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 2111102124127 its reverse (7214212011112), we get a palindrome (9325314135239).
The spelling of 2111102124127 in words is "two trillion, one hundred eleven billion, one hundred two million, one hundred twenty-four thousand, one hundred twenty-seven".
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