Base | Representation |
---|---|
bin | 11110101110001101111… |
… | …111010010010101101101 |
3 | 21110211101221012002121202 |
4 | 132232031333102111231 |
5 | 234042230021314411 |
6 | 4253513233135245 |
7 | 305346531266405 |
oct | 36561577222555 |
9 | 7424357162552 |
10 | 2111211119981 |
11 | 7443a57022a7 |
12 | 2a12003ba525 |
13 | 12411794a002 |
14 | 7427c859805 |
15 | 39db65aa83b |
hex | 1eb8dfd256d |
2111211119981 has 2 divisors, whose sum is σ = 2111211119982. Its totient is φ = 2111211119980.
The previous prime is 2111211119933. The next prime is 2111211120001. The reversal of 2111211119981 is 1899111121112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1806792988900 + 304418131081 = 1344170^2 + 551741^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111211119981 is a prime.
It is a super-2 number, since 2×21112111199812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111211118981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055605559990 + 1055605559991.
It is an arithmetic number, because the mean of its divisors is an integer number (1055605559991).
Almost surely, 22111211119981 is an apocalyptic number.
It is an amenable number.
2111211119981 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111211119981 is an equidigital number, since it uses as much as digits as its factorization.
2111211119981 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 38.
The spelling of 2111211119981 in words is "two trillion, one hundred eleven billion, two hundred eleven million, one hundred nineteen thousand, nine hundred eighty-one".
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