Base | Representation |
---|---|
bin | 11110101110001110000… |
… | …000000110011011010011 |
3 | 21110211101221120221021121 |
4 | 132232032000012123103 |
5 | 234042230100131311 |
6 | 4253513241503111 |
7 | 305346533145412 |
oct | 36561600063323 |
9 | 7424357527247 |
10 | 2111211333331 |
11 | 7443a5838621 |
12 | 2a12004a1a97 |
13 | 1241179c3159 |
14 | 7427c8b3479 |
15 | 39db65edb71 |
hex | 1eb8e0066d3 |
2111211333331 has 2 divisors, whose sum is σ = 2111211333332. Its totient is φ = 2111211333330.
The previous prime is 2111211333317. The next prime is 2111211333349. The reversal of 2111211333331 is 1333331121112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111211333331 - 25 = 2111211333299 is a prime.
It is a super-2 number, since 2×21112113333312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111211333296 and 2111211333305.
It is not a weakly prime, because it can be changed into another prime (2111211337331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055605666665 + 1055605666666.
It is an arithmetic number, because the mean of its divisors is an integer number (1055605666666).
Almost surely, 22111211333331 is an apocalyptic number.
2111211333331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111211333331 is an equidigital number, since it uses as much as digits as its factorization.
2111211333331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972, while the sum is 25.
Adding to 2111211333331 its reverse (1333331121112), we get a palindrome (3444542454443).
The spelling of 2111211333331 in words is "two trillion, one hundred eleven billion, two hundred eleven million, three hundred thirty-three thousand, three hundred thirty-one".
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