Base | Representation |
---|---|
bin | 1001100110011100011001… |
… | …00010011110111111111111 |
3 | 2202202022002002102021002201 |
4 | 10303032030202132333333 |
5 | 10231400111230004301 |
6 | 112522435222332331 |
7 | 4306205032002565 |
oct | 463161442367777 |
9 | 82668062367081 |
10 | 21112122109951 |
11 | 67aa6675a2714 |
12 | 244b806b8a0a7 |
13 | ba1b31608c22 |
14 | 52db9164ba35 |
15 | 269294b78201 |
hex | 13338c89efff |
21112122109951 has 2 divisors, whose sum is σ = 21112122109952. Its totient is φ = 21112122109950.
The previous prime is 21112122109933. The next prime is 21112122110017. The reversal of 21112122109951 is 15990122121112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21112122109951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21112122109951.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21112122109451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556061054975 + 10556061054976.
It is an arithmetic number, because the mean of its divisors is an integer number (10556061054976).
Almost surely, 221112122109951 is an apocalyptic number.
21112122109951 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112122109951 is an equidigital number, since it uses as much as digits as its factorization.
21112122109951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 37.
The spelling of 21112122109951 in words is "twenty-one trillion, one hundred twelve billion, one hundred twenty-two million, one hundred nine thousand, nine hundred fifty-one".
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