Base | Representation |
---|---|
bin | 11110101110001110000… |
… | …110111111100000100000 |
3 | 21110211102001222201120021 |
4 | 132232032012333200200 |
5 | 234042231030440000 |
6 | 4253513344323224 |
7 | 305346554411566 |
oct | 36561606774040 |
9 | 7424361881507 |
10 | 2111213140000 |
11 | 7443a6861a38 |
12 | 2a1201013514 |
13 | 1241181a65a3 |
14 | 7427cc23a36 |
15 | 39db685911a |
hex | 1eb8e1bf820 |
2111213140000 has 120 divisors (see below), whose sum is σ = 5314691566800. Its totient is φ = 824845728000.
The previous prime is 2111213139989. The next prime is 2111213140009. The reversal of 2111213140000 is 413121112.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is not an unprimeable number, because it can be changed into a prime (2111213140009) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 367450 + ... + 2087449.
It is an arithmetic number, because the mean of its divisors is an integer number (44289096390).
Almost surely, 22111213140000 is an apocalyptic number.
2111213140000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2111213140000 is an abundant number, since it is smaller than the sum of its proper divisors (3203478426800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2111213140000 is an equidigital number, since it uses as much as digits as its factorization.
2111213140000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2454972 (or 2454949 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2111213140000 its reverse (413121112), we get a palindrome (2111626261112).
The spelling of 2111213140000 in words is "two trillion, one hundred eleven billion, two hundred thirteen million, one hundred forty thousand".
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