Base | Representation |
---|---|
bin | 1001100110011100100010… |
… | …10011010010010101110101 |
3 | 2202202022021122202201010122 |
4 | 10303032101103102111311 |
5 | 10231400242203341041 |
6 | 112522451155101325 |
7 | 4306210022110331 |
oct | 463162123222565 |
9 | 82668248681118 |
10 | 21112202012021 |
11 | 67aa6a870728a |
12 | 244b8298a1845 |
13 | ba1b45033863 |
14 | 52db9c0ca7c1 |
15 | 26929bbacc4b |
hex | 1333914d2575 |
21112202012021 has 2 divisors, whose sum is σ = 21112202012022. Its totient is φ = 21112202012020.
The previous prime is 21112202011991. The next prime is 21112202012047. The reversal of 21112202012021 is 12021020221112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19979916612100 + 1132285399921 = 4469890^2 + 1064089^2 .
It is a cyclic number.
It is not a de Polignac number, because 21112202012021 - 222 = 21112197817717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21112202012071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556101006010 + 10556101006011.
It is an arithmetic number, because the mean of its divisors is an integer number (10556101006011).
Almost surely, 221112202012021 is an apocalyptic number.
It is an amenable number.
21112202012021 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112202012021 is an equidigital number, since it uses as much as digits as its factorization.
21112202012021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 21112202012021 its reverse (12021020221112), we get a palindrome (33133222233133).
The spelling of 21112202012021 in words is "twenty-one trillion, one hundred twelve billion, two hundred two million, twelve thousand, twenty-one".
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