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2111258560949 is a prime number
BaseRepresentation
bin11110101110010000110…
…100010000100110110101
321110211112020110100101122
4132232100310100212311
5234042324142422244
64253522050033325
7305350645445306
oct36562064204665
97424466410348
102111258560949
1174441a46540a
122a1214278845
1312412471a6a5
1474284c887ad
1539dba82c1ee
hex1eb90d109b5

2111258560949 has 2 divisors, whose sum is σ = 2111258560950. Its totient is φ = 2111258560948.

The previous prime is 2111258560871. The next prime is 2111258560973. The reversal of 2111258560949 is 9490658521112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1403063940100 + 708194620849 = 1184510^2 + 841543^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111258560949 - 216 = 2111258495413 is a prime.

It is a super-2 number, since 2×21112585609492 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2111258560949.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111258560979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055629280474 + 1055629280475.

It is an arithmetic number, because the mean of its divisors is an integer number (1055629280475).

Almost surely, 22111258560949 is an apocalyptic number.

It is an amenable number.

2111258560949 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111258560949 is an equidigital number, since it uses as much as digits as its factorization.

2111258560949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 53.

The spelling of 2111258560949 in words is "two trillion, one hundred eleven billion, two hundred fifty-eight million, five hundred sixty thousand, nine hundred forty-nine".