Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1001001101101101101 |
3 | 202011222000101211200012 |
4 | 3010220111021231231 |
5 | 11424343241442312 |
6 | 240554121143005 |
7 | 21152666436566 |
oct | 3045025115555 |
9 | 664860354605 |
10 | 211130030957 |
11 | 815a344219a |
12 | 34b0302aa65 |
13 | 16ba9173401 |
14 | a30c35d16d |
15 | 575a64b322 |
hex | 3128549b6d |
211130030957 has 2 divisors, whose sum is σ = 211130030958. Its totient is φ = 211130030956.
The previous prime is 211130030939. The next prime is 211130030999. The reversal of 211130030957 is 759030031112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135732559561 + 75397471396 = 368419^2 + 274586^2 .
It is a cyclic number.
It is not a de Polignac number, because 211130030957 - 216 = 211129965421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211130030927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565015478 + 105565015479.
It is an arithmetic number, because the mean of its divisors is an integer number (105565015479).
Almost surely, 2211130030957 is an apocalyptic number.
It is an amenable number.
211130030957 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130030957 is an equidigital number, since it uses as much as digits as its factorization.
211130030957 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670, while the sum is 32.
The spelling of 211130030957 in words is "two hundred eleven billion, one hundred thirty million, thirty thousand, nine hundred fifty-seven".
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