Base | Representation |
---|---|
bin | 1001100110011110001111… |
… | …00010101100111110110111 |
3 | 2202202101122002010001110202 |
4 | 10303033013202230332313 |
5 | 10231404123134213332 |
6 | 112523121343511115 |
7 | 4306241412062426 |
oct | 463170742547667 |
9 | 82671562101422 |
10 | 21113112022967 |
11 | 6800025356a48 |
12 | 244ba425b849b |
13 | ba1c5b723a83 |
14 | 52dc46cd12bd |
15 | 269301a15a62 |
hex | 1333c78acfb7 |
21113112022967 has 2 divisors, whose sum is σ = 21113112022968. Its totient is φ = 21113112022966.
The previous prime is 21113112022949. The next prime is 21113112023011. The reversal of 21113112022967 is 76922021131112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21113112022967 - 244 = 3520925978551 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21113112022967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21113112022567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556556011483 + 10556556011484.
It is an arithmetic number, because the mean of its divisors is an integer number (10556556011484).
Almost surely, 221113112022967 is an apocalyptic number.
21113112022967 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113112022967 is an equidigital number, since it uses as much as digits as its factorization.
21113112022967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 38.
The spelling of 21113112022967 in words is "twenty-one trillion, one hundred thirteen billion, one hundred twelve million, twenty-two thousand, nine hundred sixty-seven".
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