Base | Representation |
---|---|
bin | 11110101110010100101… |
… | …010001100111000001111 |
3 | 21110211200201202212120012 |
4 | 132232110222030320033 |
5 | 234042442144024403 |
6 | 4253532311543435 |
7 | 305352360446624 |
oct | 36562452147017 |
9 | 7424621685505 |
10 | 2111323033103 |
11 | 7444528a0289 |
12 | 2a123198ab7b |
13 | 124134ba20ab |
14 | 7428d66c34b |
15 | 39dc1314ed8 |
hex | 1eb94a8ce0f |
2111323033103 has 2 divisors, whose sum is σ = 2111323033104. Its totient is φ = 2111323033102.
The previous prime is 2111323033073. The next prime is 2111323033111. The reversal of 2111323033103 is 3013303231112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111323033103 - 218 = 2111322770959 is a prime.
It is a super-2 number, since 2×21113230331032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111323003103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055661516551 + 1055661516552.
It is an arithmetic number, because the mean of its divisors is an integer number (1055661516552).
Almost surely, 22111323033103 is an apocalyptic number.
2111323033103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111323033103 is an equidigital number, since it uses as much as digits as its factorization.
2111323033103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 2111323033103 its reverse (3013303231112), we get a palindrome (5124626264215).
The spelling of 2111323033103 in words is "two trillion, one hundred eleven billion, three hundred twenty-three million, thirty-three thousand, one hundred three".
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