211134202431127 has 2 divisors, whose sum is σ = 211134202431128. Its totient is φ = 211134202431126.

The previous prime is 211134202431007. The next prime is 211134202431227. The reversal of 211134202431127 is 721134202431112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211134202431127 - 2¹¹ = 211134202429079 is a prime.

It is a super-2 number, since 2×211134202431127² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211134202431092 and 211134202431101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211134202431227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105567101215563 + 105567101215564.

It is an arithmetic number, because the mean of its divisors is an integer number (105567101215564).

Almost surely, 2^{211134202431127} is an apocalyptic number.

211134202431127 is a deficient number, since it is larger than the sum of its proper divisors (1).

211134202431127 is an equidigital number, since it uses as much as digits as its factorization.

211134202431127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 211134202431127 its reverse (721134202431112), we get a palindrome (932268404862239).

The spelling of 211134202431127 in words is "two hundred eleven trillion, one hundred thirty-four billion, two hundred two million, four hundred thirty-one thousand, one hundred twenty-seven".