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211140041112 = 2332711132929571
BaseRepresentation
bin1100010010100011101…
…1010101100110011000
3202011222201020102000200
43010220323111212120
511424403322303422
6240555115502200
721153150510660
oct3045073254630
9664881212020
10211140041112
11815a9059a50
1234b06457960
1316bab269790
14a30d8071a0
15575b4772ac
hex3128ed5998

211140041112 has 192 divisors, whose sum is σ = 767782229760. Its totient is φ = 50622969600.

The previous prime is 211140041087. The next prime is 211140041131.

211140041112 is a `hidden beast` number, since 2 + 111 + 400 + 41 + 112 = 666.

211140041112 is nontrivially palindromic in base 10.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1392714 + ... + 1536857.

It is an arithmetic number, because the mean of its divisors is an integer number (3998865780).

Almost surely, 2211140041112 is an apocalyptic number.

211140041112 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is an amenable number.

211140041112 is an abundant number, since it is smaller than the sum of its proper divisors (556642188648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211140041112 is a wasteful number, since it uses less digits than its factorization.

211140041112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2929614 (or 2929607 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

It can be divided in two parts, 2111400 and 41112, that added together give a palindrome (2152512).

The spelling of 211140041112 in words is "two hundred eleven billion, one hundred forty million, forty-one thousand, one hundred twelve".