21114120044231 has 2 divisors, whose sum is σ = 21114120044232. Its totient is φ = 21114120044230.

The previous prime is 21114120044189. The next prime is 21114120044233. The reversal of 21114120044231 is 13244002141112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21114120044231 - 2⁶ = 21114120044167 is a prime.

It is a super-3 number, since 3×21114120044231³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 21114120044233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21114120044231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21114120044233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557060022115 + 10557060022116.

It is an arithmetic number, because the mean of its divisors is an integer number (10557060022116).

Almost surely, 2^{21114120044231} is an apocalyptic number.

21114120044231 is a deficient number, since it is larger than the sum of its proper divisors (1).

21114120044231 is an equidigital number, since it uses as much as digits as its factorization.

21114120044231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 21114120044231 its reverse (13244002141112), we get a palindrome (34358122185343).

The spelling of 21114120044231 in words is "twenty-one trillion, one hundred fourteen billion, one hundred twenty million, forty-four thousand, two hundred thirty-one".