2111412132000 has 288 divisors, whose sum is σ = 7497886556160. Its totient is φ = 562706265600.

The previous prime is 2111412131987. The next prime is 2111412132029. The reversal of 2111412132000 is 2312141112.

2111412132000 is a `hidden beast` number, since 211 + 1 + 41 + 213 + 200 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a super-2 number, since 2×2111412132000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 63307329 + ... + 63340671.

It is an arithmetic number, because the mean of its divisors is an integer number (26034328320).

Almost surely, 2^{2111412132000} is an apocalyptic number.

2111412132000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2111412132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3748943278080).

2111412132000 is an abundant number, since it is smaller than the sum of its proper divisors (5386474424160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2111412132000 is a wasteful number, since it uses less digits than its factorization.

2111412132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35133 (or 35112 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 2111412132000 its reverse (2312141112), we get a palindrome (2113724273112).

The spelling of 2111412132000 in words is "two trillion, one hundred eleven billion, four hundred twelve million, one hundred thirty-two thousand".