Base | Representation |
---|---|
bin | 1100010010100100010… |
… | …0000010010010010100 |
3 | 202011222212112020212002 |
4 | 3010221010002102110 |
5 | 11424404413240200 |
6 | 240555240414432 |
7 | 21153206055521 |
oct | 3045104022224 |
9 | 664885466762 |
10 | 211142321300 |
11 | 815aa3770a9 |
12 | 34b07177418 |
13 | 16bab8875c1 |
14 | a30dc3c148 |
15 | 575b777bd5 |
hex | 3129102494 |
211142321300 has 36 divisors (see below), whose sum is σ = 473978113980. Its totient is φ = 81544619520.
The previous prime is 211142321279. The next prime is 211142321309. The reversal of 211142321300 is 3123241112.
It can be written as a sum of positive squares in 6 ways, for example, as 6054707344 + 205087613956 = 77812^2 + 452866^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211142321309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 36400949 + ... + 36406748.
Almost surely, 2211142321300 is an apocalyptic number.
211142321300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211142321300 is an abundant number, since it is smaller than the sum of its proper divisors (262835792680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211142321300 is a wasteful number, since it uses less digits than its factorization.
211142321300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72807740 (or 72807733 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 211142321300 its reverse (3123241112), we get a palindrome (214265562412).
The spelling of 211142321300 in words is "two hundred eleven billion, one hundred forty-two million, three hundred twenty-one thousand, three hundred".
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