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2111504501413 is a prime number
BaseRepresentation
bin11110101110011111011…
…110011100101010100101
321110212011101020102021201
4132232133132130222211
5234043330123021123
64254002313242501
7305360023062016
oct36563736345245
97425141212251
102111504501413
1174453627609a
122a1282703431
1312416366b3a8
14742a97c900d
1539dd220d5ad
hex1eb9f79caa5

2111504501413 has 2 divisors, whose sum is σ = 2111504501414. Its totient is φ = 2111504501412.

The previous prime is 2111504501401. The next prime is 2111504501417. The reversal of 2111504501413 is 3141054051112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1233792220644 + 877712280769 = 1110762^2 + 936863^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111504501413 - 213 = 2111504493221 is a prime.

It is a super-3 number, since 3×21115045014133 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111504501417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055752250706 + 1055752250707.

It is an arithmetic number, because the mean of its divisors is an integer number (1055752250707).

Almost surely, 22111504501413 is an apocalyptic number.

It is an amenable number.

2111504501413 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111504501413 is an equidigital number, since it uses as much as digits as its factorization.

2111504501413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 2111504501413 its reverse (3141054051112), we get a palindrome (5252558552525).

The spelling of 2111504501413 in words is "two trillion, one hundred eleven billion, five hundred four million, five hundred one thousand, four hundred thirteen".