Base | Representation |
---|---|
bin | 11110101110100010001… |
… | …100001110011011000101 |
3 | 21110212021112221211121120 |
4 | 132232202030032123011 |
5 | 234043423303244013 |
6 | 4254011021504153 |
7 | 305361115223430 |
oct | 36564214163305 |
9 | 7425245854546 |
10 | 2111550056133 |
11 | 744559a60021 |
12 | 2a1295a12059 |
13 | 12416cc2b34b |
14 | 742b1886817 |
15 | 39dd620b123 |
hex | 1eba230e6c5 |
2111550056133 has 32 divisors (see below), whose sum is σ = 3288089333760. Its totient is φ = 1180198278720.
The previous prime is 2111550056131. The next prime is 2111550056153. The reversal of 2111550056133 is 3316500551112.
It is not a de Polignac number, because 2111550056133 - 21 = 2111550056131 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2111550056094 and 2111550056103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2111550056131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 940038 + ... + 2259816.
It is an arithmetic number, because the mean of its divisors is an integer number (102752791680).
Almost surely, 22111550056133 is an apocalyptic number.
It is an amenable number.
2111550056133 is a deficient number, since it is larger than the sum of its proper divisors (1176539277627).
2111550056133 is a wasteful number, since it uses less digits than its factorization.
2111550056133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1321457.
The product of its (nonzero) digits is 13500, while the sum is 33.
The spelling of 2111550056133 in words is "two trillion, one hundred eleven billion, five hundred fifty million, fifty-six thousand, one hundred thirty-three".
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