Base | Representation |
---|---|
bin | 110000000001010111010101… |
… | …110101001101100000000011 |
3 | 1000200210112011010120002002212 |
4 | 300001113111311031200003 |
5 | 210140300112132422042 |
6 | 2025103540330332335 |
7 | 62325461145411035 |
oct | 6001272565154003 |
9 | 1020715133502085 |
10 | 211200014342147 |
11 | 61327472139976 |
12 | 1b82bb8958a0ab |
13 | 90b00ca98417c |
14 | 3a221c7131c55 |
15 | 1963be50a2482 |
hex | c015d5d4d803 |
211200014342147 has 2 divisors, whose sum is σ = 211200014342148. Its totient is φ = 211200014342146.
The previous prime is 211200014342029. The next prime is 211200014342179. The reversal of 211200014342147 is 741243410002112.
It is an a-pointer prime, because the next prime (211200014342179) can be obtained adding 211200014342147 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211200014342147 - 226 = 211199947233283 is a prime.
It is not a weakly prime, because it can be changed into another prime (211200014342347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600007171073 + 105600007171074.
It is an arithmetic number, because the mean of its divisors is an integer number (105600007171074).
Almost surely, 2211200014342147 is an apocalyptic number.
211200014342147 is a deficient number, since it is larger than the sum of its proper divisors (1).
211200014342147 is an equidigital number, since it uses as much as digits as its factorization.
211200014342147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 32.
Adding to 211200014342147 its reverse (741243410002112), we get a palindrome (952443424344259).
The spelling of 211200014342147 in words is "two hundred eleven trillion, two hundred billion, fourteen million, three hundred forty-two thousand, one hundred forty-seven".
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