Base | Representation |
---|---|
bin | 1001100110101011000101… |
… | …10100000110100101000111 |
3 | 2202210001102221200020000212 |
4 | 10303111202310012211013 |
5 | 10232012241034120124 |
6 | 112530222150430035 |
7 | 4306604405065112 |
oct | 463254264064507 |
9 | 82701387606025 |
10 | 21120012020039 |
11 | 6802a46207969 |
12 | 245124936231b |
13 | ba27bb0b4a8a |
14 | 5302dd459579 |
15 | 2695a767940e |
hex | 133562d06947 |
21120012020039 has 2 divisors, whose sum is σ = 21120012020040. Its totient is φ = 21120012020038.
The previous prime is 21120012020017. The next prime is 21120012020047. The reversal of 21120012020039 is 93002021002112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21120012020039 - 28 = 21120012019783 is a prime.
It is a super-4 number, since 4×211200120200394 (a number of 54 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21120012019996 and 21120012020023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21120012020069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560006010019 + 10560006010020.
It is an arithmetic number, because the mean of its divisors is an integer number (10560006010020).
Almost surely, 221120012020039 is an apocalyptic number.
21120012020039 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120012020039 is an equidigital number, since it uses as much as digits as its factorization.
21120012020039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
The spelling of 21120012020039 in words is "twenty-one trillion, one hundred twenty billion, twelve million, twenty thousand, thirty-nine".
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