Base | Representation |
---|---|
bin | 110000000001010111100000… |
… | …111010010010010110011111 |
3 | 1000200210112122002022202110222 |
4 | 300001113200322102112133 |
5 | 210140301002224101421 |
6 | 2025104011010351555 |
7 | 62325465563356112 |
oct | 6001274072222637 |
9 | 1020715562282428 |
10 | 211200200222111 |
11 | 61327558058281 |
12 | 1b83001b88b5bb |
13 | 90b012a336509 |
14 | 3a22203aba579 |
15 | 1963c0656ccab |
hex | c015e0e9259f |
211200200222111 has 2 divisors, whose sum is σ = 211200200222112. Its totient is φ = 211200200222110.
The previous prime is 211200200222107. The next prime is 211200200222131. The reversal of 211200200222111 is 111222002002112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211200200222111 - 22 = 211200200222107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211200200222111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211200200222131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600100111055 + 105600100111056.
It is an arithmetic number, because the mean of its divisors is an integer number (105600100111056).
Almost surely, 2211200200222111 is an apocalyptic number.
211200200222111 is a deficient number, since it is larger than the sum of its proper divisors (1).
211200200222111 is an equidigital number, since it uses as much as digits as its factorization.
211200200222111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 211200200222111 its reverse (111222002002112), we get a palindrome (322422202224223).
The spelling of 211200200222111 in words is "two hundred eleven trillion, two hundred billion, two hundred million, two hundred twenty-two thousand, one hundred eleven".
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