Base | Representation |
---|---|
bin | 110000000001011000011100… |
… | …100000111001100111010101 |
3 | 1000200210122012202221220110121 |
4 | 300001120130200321213111 |
5 | 210140310024222401044 |
6 | 2025104254131351541 |
7 | 62325532425136015 |
oct | 6001303440714725 |
9 | 1020718182856417 |
10 | 211201200200149 |
11 | 61327a20566605 |
12 | 1b83025a7525b1 |
13 | 90b02595666b3 |
14 | 3a2229a81dc45 |
15 | 1963c64247984 |
hex | c0161c8399d5 |
211201200200149 has 2 divisors, whose sum is σ = 211201200200150. Its totient is φ = 211201200200148.
The previous prime is 211201200200093. The next prime is 211201200200153. The reversal of 211201200200149 is 941002002102112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135743051377924 + 75458148822225 = 11650882^2 + 8686665^2 .
It is a cyclic number.
It is not a de Polignac number, because 211201200200149 - 213 = 211201200191957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211201200204149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600600100074 + 105600600100075.
It is an arithmetic number, because the mean of its divisors is an integer number (105600600100075).
Almost surely, 2211201200200149 is an apocalyptic number.
It is an amenable number.
211201200200149 is a deficient number, since it is larger than the sum of its proper divisors (1).
211201200200149 is an equidigital number, since it uses as much as digits as its factorization.
211201200200149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
The spelling of 211201200200149 in words is "two hundred eleven trillion, two hundred one billion, two hundred million, two hundred thousand, one hundred forty-nine".
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