Base | Representation |
---|---|
bin | 111110111100010… |
… | …1011111101000111 |
3 | 12110012010022221111 |
4 | 1331320223331013 |
5 | 13311133341403 |
6 | 545323425451 |
7 | 103223543455 |
oct | 17570537507 |
9 | 5405108844 |
10 | 2112012103 |
11 | 9941a2a53 |
12 | 4ab385287 |
13 | 278735506 |
14 | 1606d59d5 |
15 | c563b56d |
hex | 7de2bf47 |
2112012103 has 2 divisors, whose sum is σ = 2112012104. Its totient is φ = 2112012102.
The previous prime is 2112012073. The next prime is 2112012121. The reversal of 2112012103 is 3012102112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112012103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112012143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056006051 + 1056006052.
It is an arithmetic number, because the mean of its divisors is an integer number (1056006052).
Almost surely, 22112012103 is an apocalyptic number.
2112012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112012103 is an equidigital number, since it uses as much as digits as its factorization.
2112012103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 2112012103 is about 45956.6328509825. The cubic root of 2112012103 is about 1283.0161828010.
Adding to 2112012103 its reverse (3012102112), we get a palindrome (5124114215).
Subtracting 2112012103 from its reverse (3012102112), we obtain a palindrome (900090009).
The spelling of 2112012103 in words is "two billion, one hundred twelve million, twelve thousand, one hundred three".
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