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2112014040217 is a prime number
BaseRepresentation
bin11110101110111101110…
…110001011110010011001
321110220110220000200010021
4132232331312023302121
5234100401043241332
64254125034350441
7305405451064624
oct36567566136231
97426426020107
102112014040217
11744777958144
122a13a528b421
131242150b3143
1474317344dbb
1539e11d0cc97
hex1ebbdd8bc99

2112014040217 has 2 divisors, whose sum is σ = 2112014040218. Its totient is φ = 2112014040216.

The previous prime is 2112014040109. The next prime is 2112014040259. The reversal of 2112014040217 is 7120404102112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1297220769936 + 814793270281 = 1138956^2 + 902659^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112014040217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2112014040191 and 2112014040200.

It is not a weakly prime, because it can be changed into another prime (2112014046217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056007020108 + 1056007020109.

It is an arithmetic number, because the mean of its divisors is an integer number (1056007020109).

Almost surely, 22112014040217 is an apocalyptic number.

It is an amenable number.

2112014040217 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112014040217 is an equidigital number, since it uses as much as digits as its factorization.

2112014040217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 896, while the sum is 25.

Adding to 2112014040217 its reverse (7120404102112), we get a palindrome (9232418142329).

The spelling of 2112014040217 in words is "two trillion, one hundred twelve billion, fourteen million, forty thousand, two hundred seventeen".