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211202013020 = 22510560100651
BaseRepresentation
bin1100010010110010011…
…1101111011101011100
3202012011000211220111112
43010230213233131130
511430020203404040
6241005212041152
721154532330045
oct3045447573534
9665130756445
10211202013020
11816300373a9
1234b231631b8
1316bbb05714b
14a317b398cc
155761b19365
hex312c9ef75c

211202013020 has 12 divisors (see below), whose sum is σ = 443524227384. Its totient is φ = 84480805200.

The previous prime is 211202013013. The next prime is 211202013047. The reversal of 211202013020 is 20310202112.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 211202012986 and 211202013004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5280050306 + ... + 5280050345.

It is an arithmetic number, because the mean of its divisors is an integer number (36960352282).

Almost surely, 2211202013020 is an apocalyptic number.

211202013020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

211202013020 is an abundant number, since it is smaller than the sum of its proper divisors (232322214364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211202013020 is a wasteful number, since it uses less digits than its factorization.

211202013020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10560100660 (or 10560100658 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 211202013020 its reverse (20310202112), we get a palindrome (231512215132).

The spelling of 211202013020 in words is "two hundred eleven billion, two hundred two million, thirteen thousand, twenty".

Divisors: 1 2 4 5 10 20 10560100651 21120201302 42240402604 52800503255 105601006510 211202013020