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2112100012103 is a prime number
BaseRepresentation
bin11110101111000010111…
…110001001000001000111
321110220200212210111101012
4132233002332021001013
5234101040100341403
64254141345152435
7305410543612544
oct36570276110107
97426625714335
102112100012103
11744811438094
122a140a02b71b
13124229b54793
1474324923bcb
1539e19640ed8
hex1ebc2f89047

2112100012103 has 2 divisors, whose sum is σ = 2112100012104. Its totient is φ = 2112100012102.

The previous prime is 2112100012067. The next prime is 2112100012109. The reversal of 2112100012103 is 3012100012112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2112100012103 - 218 = 2112099749959 is a prime.

It is a super-2 number, since 2×21121000121032 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112100012109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056050006051 + 1056050006052.

It is an arithmetic number, because the mean of its divisors is an integer number (1056050006052).

Almost surely, 22112100012103 is an apocalyptic number.

2112100012103 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112100012103 is an equidigital number, since it uses as much as digits as its factorization.

2112100012103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 2112100012103 its reverse (3012100012112), we get a palindrome (5124200024215).

Subtracting 2112100012103 from its reverse (3012100012112), we obtain a palindrome (900000000009).

The spelling of 2112100012103 in words is "two trillion, one hundred twelve billion, one hundred million, twelve thousand, one hundred three".