Base | Representation |
---|---|
bin | 1001100110101101000111… |
… | …10011001100111111100111 |
3 | 2202210011020221020100100221 |
4 | 10303112203303030333213 |
5 | 10232022004142200312 |
6 | 112530522255145211 |
7 | 4306643414251204 |
oct | 463264363147747 |
9 | 82704227210327 |
10 | 21121102303207 |
11 | 6803455695835 |
12 | 24514b2515207 |
13 | ba2932c42a4a |
14 | 5303a4188cab |
15 | 26961d241207 |
hex | 1335a3cccfe7 |
21121102303207 has 2 divisors, whose sum is σ = 21121102303208. Its totient is φ = 21121102303206.
The previous prime is 21121102303153. The next prime is 21121102303229. The reversal of 21121102303207 is 70230320112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21121102303207 - 227 = 21120968085479 is a prime.
It is a super-2 number, since 2×211211023032072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21121102303237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560551151603 + 10560551151604.
It is an arithmetic number, because the mean of its divisors is an integer number (10560551151604).
Almost surely, 221121102303207 is an apocalyptic number.
21121102303207 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121102303207 is an equidigital number, since it uses as much as digits as its factorization.
21121102303207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 21121102303207 its reverse (70230320112112), we get a palindrome (91351422415319).
The spelling of 21121102303207 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred two million, three hundred three thousand, two hundred seven".
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