Base | Representation |
---|---|
bin | 1001100110101101010011… |
… | …01100000101100011000111 |
3 | 2202210011111211010210110102 |
4 | 10303112221230011203013 |
5 | 10232022204440212444 |
6 | 112530540144514315 |
7 | 4306646024105336 |
oct | 463265154054307 |
9 | 82704454123412 |
10 | 21121201100999 |
11 | 68034a6435aaa |
12 | 245151b61b99b |
13 | ba294a55528c |
14 | 5303b3345d1d |
15 | 269626c5984e |
hex | 1335a9b058c7 |
21121201100999 has 2 divisors, whose sum is σ = 21121201101000. Its totient is φ = 21121201100998.
The previous prime is 21121201100903. The next prime is 21121201101041. The reversal of 21121201100999 is 99900110212112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21121201100999 - 236 = 21052481624263 is a prime.
It is a super-2 number, since 2×211212011009992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21121201100099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560600550499 + 10560600550500.
It is an arithmetic number, because the mean of its divisors is an integer number (10560600550500).
Almost surely, 221121201100999 is an apocalyptic number.
21121201100999 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121201100999 is an equidigital number, since it uses as much as digits as its factorization.
21121201100999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 38.
The spelling of 21121201100999 in words is "twenty-one trillion, one hundred twenty-one billion, two hundred one million, one hundred thousand, nine hundred ninety-nine".
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