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211212104351 is a prime number
BaseRepresentation
bin1100010010110100111…
…0001111001010011111
3202012011201211121012112
43010231032033022133
511430030244314401
6241010212224235
721155014156613
oct3045516171237
9665151747175
10211212104351
11816357aa146
1234b2660b07b
1316bc017b451
14a319205343
15576295e3bb
hex312d38f29f

211212104351 has 2 divisors, whose sum is σ = 211212104352. Its totient is φ = 211212104350.

The previous prime is 211212104347. The next prime is 211212104353. The reversal of 211212104351 is 153401212112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211212104351 - 22 = 211212104347 is a prime.

It is a super-2 number, since 2×2112121043512 (a number of 23 digits) contains 22 as substring.

Together with 211212104353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211212104353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606052175 + 105606052176.

It is an arithmetic number, because the mean of its divisors is an integer number (105606052176).

Almost surely, 2211212104351 is an apocalyptic number.

211212104351 is a deficient number, since it is larger than the sum of its proper divisors (1).

211212104351 is an equidigital number, since it uses as much as digits as its factorization.

211212104351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 211212104351 its reverse (153401212112), we get a palindrome (364613316463).

The spelling of 211212104351 in words is "two hundred eleven billion, two hundred twelve million, one hundred four thousand, three hundred fifty-one".