Search a number
-
+
211212110020073 is a prime number
BaseRepresentation
bin110000000001100010100110…
…110010100011110111101001
31000200211200101002201011220012
4300001202212302203313221
5210140444400131120243
62025113300454541305
762326366661106131
oct6001424662436751
91020750332634805
10211212110020073
11613316098aa808
121b8323a4367835
1390b12a78a8146
143a22a13737ac1
1519641a1e21d18
hexc018a6ca3de9

211212110020073 has 2 divisors, whose sum is σ = 211212110020074. Its totient is φ = 211212110020072.

The previous prime is 211212110020031. The next prime is 211212110020157. The reversal of 211212110020073 is 370020011212112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206854925532304 + 4357184487769 = 14382452^2 + 2087387^2 .

It is a cyclic number.

It is not a de Polignac number, because 211212110020073 - 220 = 211212108971497 is a prime.

It is a super-2 number, since 2×2112121100200732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211212110020273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606055010036 + 105606055010037.

It is an arithmetic number, because the mean of its divisors is an integer number (105606055010037).

Almost surely, 2211212110020073 is an apocalyptic number.

It is an amenable number.

211212110020073 is a deficient number, since it is larger than the sum of its proper divisors (1).

211212110020073 is an equidigital number, since it uses as much as digits as its factorization.

211212110020073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 211212110020073 its reverse (370020011212112), we get a palindrome (581232121232185).

The spelling of 211212110020073 in words is "two hundred eleven trillion, two hundred twelve billion, one hundred ten million, twenty thousand, seventy-three".