211212110020157 has 2 divisors, whose sum is σ = 211212110020158. Its totient is φ = 211212110020156.

The previous prime is 211212110020073. The next prime is 211212110020159. The reversal of 211212110020157 is 751020011212112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 162835438968601 + 48376671051556 = 12760699^2 + 6955334^2 .

It is a cyclic number.

It is not a de Polignac number, because 211212110020157 - 2²⁸ = 211211841584701 is a prime.

It is a super-2 number, since 2×211212110020157² (a number of 29 digits) contains 22 as substring.

Together with 211212110020159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211212110020159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606055010078 + 105606055010079.

It is an arithmetic number, because the mean of its divisors is an integer number (105606055010079).

Almost surely, 2^{211212110020157} is an apocalyptic number.

It is an amenable number.

211212110020157 is a deficient number, since it is larger than the sum of its proper divisors (1).

211212110020157 is an equidigital number, since it uses as much as digits as its factorization.

211212110020157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 26.

Adding to 211212110020157 its reverse (751020011212112), we get a palindrome (962232121232269).

The spelling of 211212110020157 in words is "two hundred eleven trillion, two hundred twelve billion, one hundred ten million, twenty thousand, one hundred fifty-seven".