Base | Representation |
---|---|
bin | 1100010010110101001… |
… | …0100010010010001111 |
3 | 202012011210221212000102 |
4 | 3010231102202102033 |
5 | 11430031041344442 |
6 | 241010252321315 |
7 | 21155026562204 |
oct | 3045522422217 |
9 | 665153855012 |
10 | 211213231247 |
11 | 816363a9867 |
12 | 34b26a7323b |
13 | 16bc0484355 |
14 | a319419cab |
15 | 5762ad3232 |
hex | 312d4a248f |
211213231247 has 2 divisors, whose sum is σ = 211213231248. Its totient is φ = 211213231246.
The previous prime is 211213231181. The next prime is 211213231267. The reversal of 211213231247 is 742132312112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211213231247 - 222 = 211209036943 is a prime.
It is a super-2 number, since 2×2112132312472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211213231267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606615623 + 105606615624.
It is an arithmetic number, because the mean of its divisors is an integer number (105606615624).
Almost surely, 2211213231247 is an apocalyptic number.
211213231247 is a deficient number, since it is larger than the sum of its proper divisors (1).
211213231247 is an equidigital number, since it uses as much as digits as its factorization.
211213231247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4032, while the sum is 29.
Adding to 211213231247 its reverse (742132312112), we get a palindrome (953345543359).
The spelling of 211213231247 in words is "two hundred eleven billion, two hundred thirteen million, two hundred thirty-one thousand, two hundred forty-seven".
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