Base | Representation |
---|---|
bin | 11110101111001000111… |
… | …111110000101011100011 |
3 | 21110220221221000021220111 |
4 | 132233020333300223203 |
5 | 234101241440200003 |
6 | 4254155355552151 |
7 | 305413212055501 |
oct | 36571077605343 |
9 | 7426857007814 |
10 | 2112201100003 |
11 | 744863501a05 |
12 | 2a1437a5b657 |
13 | 124244a894c7 |
14 | 74334119671 |
15 | 39e2345ce6d |
hex | 1ebc8ff0ae3 |
2112201100003 has 2 divisors, whose sum is σ = 2112201100004. Its totient is φ = 2112201100002.
The previous prime is 2112201099971. The next prime is 2112201100007. The reversal of 2112201100003 is 3000011022112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112201100003 - 25 = 2112201099971 is a prime.
It is a super-2 number, since 2×21122011000032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112201100007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056100550001 + 1056100550002.
It is an arithmetic number, because the mean of its divisors is an integer number (1056100550002).
Almost surely, 22112201100003 is an apocalyptic number.
2112201100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112201100003 is an equidigital number, since it uses as much as digits as its factorization.
2112201100003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2112201100003 its reverse (3000011022112), we get a palindrome (5112212122115).
The spelling of 2112201100003 in words is "two trillion, one hundred twelve billion, two hundred one million, one hundred thousand, three".
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