Base | Representation |
---|---|
bin | 11110101111001000111… |
… | …111110000101011100111 |
3 | 21110220221221000021220122 |
4 | 132233020333300223213 |
5 | 234101241440200012 |
6 | 4254155355552155 |
7 | 305413212055505 |
oct | 36571077605347 |
9 | 7426857007818 |
10 | 2112201100007 |
11 | 744863501a09 |
12 | 2a1437a5b65b |
13 | 124244a894cb |
14 | 74334119675 |
15 | 39e2345ce72 |
hex | 1ebc8ff0ae7 |
2112201100007 has 2 divisors, whose sum is σ = 2112201100008. Its totient is φ = 2112201100006.
The previous prime is 2112201100003. The next prime is 2112201100021. The reversal of 2112201100007 is 7000011022112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112201100007 - 22 = 2112201100003 is a prime.
It is a super-2 number, since 2×21122011000072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112201100003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056100550003 + 1056100550004.
It is an arithmetic number, because the mean of its divisors is an integer number (1056100550004).
Almost surely, 22112201100007 is an apocalyptic number.
2112201100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112201100007 is an equidigital number, since it uses as much as digits as its factorization.
2112201100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 2112201100007 its reverse (7000011022112), we get a palindrome (9112212122119).
The spelling of 2112201100007 in words is "two trillion, one hundred twelve billion, two hundred one million, one hundred thousand, seven".
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