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21122014423 is a prime number
BaseRepresentation
bin10011101010111110…
…000101110011010111
32000112000210111200111
4103222332011303113
5321224213430143
613411530023451
71345265105656
oct235276056327
960460714614
1021122014423
118a59910074
124115877b87
131cb7c958b3
14104531519d
158394ee99d
hex4eaf85cd7

21122014423 has 2 divisors, whose sum is σ = 21122014424. Its totient is φ = 21122014422.

The previous prime is 21122014421. The next prime is 21122014427. The reversal of 21122014423 is 32441022112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21122014423 - 21 = 21122014421 is a prime.

It is a super-2 number, since 2×211220144232 (a number of 21 digits) contains 22 as substring.

Together with 21122014421, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 21122014394 and 21122014403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21122014421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561007211 + 10561007212.

It is an arithmetic number, because the mean of its divisors is an integer number (10561007212).

Almost surely, 221122014423 is an apocalyptic number.

21122014423 is a deficient number, since it is larger than the sum of its proper divisors (1).

21122014423 is an equidigital number, since it uses as much as digits as its factorization.

21122014423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 21122014423 its reverse (32441022112), we get a palindrome (53563036535).

The spelling of 21122014423 in words is "twenty-one billion, one hundred twenty-two million, fourteen thousand, four hundred twenty-three".