Base | Representation |
---|---|
bin | 10011101010111110… |
… | …011111100011111101 |
3 | 2000112000222212102021 |
4 | 103222332133203331 |
5 | 321224230314213 |
6 | 13411532200141 |
7 | 1345266025405 |
oct | 235276374375 |
9 | 60460885367 |
10 | 21122119933 |
11 | 8a59982372 |
12 | 4115909051 |
13 | 1cb8001925 |
14 | 1045341805 |
15 | 839520d8d |
hex | 4eaf9f8fd |
21122119933 has 2 divisors, whose sum is σ = 21122119934. Its totient is φ = 21122119932.
The previous prime is 21122119901. The next prime is 21122119987. The reversal of 21122119933 is 33991122112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20085408729 + 1036711204 = 141723^2 + 32198^2 .
It is a cyclic number.
It is not a de Polignac number, because 21122119933 - 25 = 21122119901 is a prime.
It is a super-3 number, since 3×211221199333 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21122129933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561059966 + 10561059967.
It is an arithmetic number, because the mean of its divisors is an integer number (10561059967).
Almost surely, 221122119933 is an apocalyptic number.
It is an amenable number.
21122119933 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122119933 is an equidigital number, since it uses as much as digits as its factorization.
21122119933 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832, while the sum is 34.
The spelling of 21122119933 in words is "twenty-one billion, one hundred twenty-two million, one hundred nineteen thousand, nine hundred thirty-three".
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