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2112220000031 is a prime number
BaseRepresentation
bin11110101111001010000…
…111110110111100011111
321110221000020120111212112
4132233022013312330133
5234101311310000111
64254201313024235
7305413531523561
oct36571207667437
97427006514775
102112220000031
11744873140869
122a144225507b
1312424897605b
1474336839331
1539e24e42e8b
hex1ebca1f6f1f

2112220000031 has 2 divisors, whose sum is σ = 2112220000032. Its totient is φ = 2112220000030.

The previous prime is 2112220000003. The next prime is 2112220000043. The reversal of 2112220000031 is 1300000222112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2112220000031 - 234 = 2095040130847 is a prime.

It is a super-2 number, since 2×21122200000312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112219999970 and 2112220000015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112220000001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056110000015 + 1056110000016.

It is an arithmetic number, because the mean of its divisors is an integer number (1056110000016).

Almost surely, 22112220000031 is an apocalyptic number.

2112220000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112220000031 is an equidigital number, since it uses as much as digits as its factorization.

2112220000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 2112220000031 its reverse (1300000222112), we get a palindrome (3412220222143).

The spelling of 2112220000031 in words is "two trillion, one hundred twelve billion, two hundred twenty million, thirty-one", and thus it is an aban number.