Base | Representation |
---|---|
bin | 1001100110101111001011… |
… | …11000100101011010110111 |
3 | 2202210021010012110111111001 |
4 | 10303113211320211122313 |
5 | 10232031242004311411 |
6 | 112531224302424131 |
7 | 4310013036150202 |
oct | 463274570453267 |
9 | 82707105414431 |
10 | 21122211010231 |
11 | 6803974507831 |
12 | 2451761892047 |
13 | ba2a7b8518c6 |
14 | 53046b512939 |
15 | 269685746dc1 |
hex | 1335e5e256b7 |
21122211010231 has 2 divisors, whose sum is σ = 21122211010232. Its totient is φ = 21122211010230.
The previous prime is 21122211010207. The next prime is 21122211010237. The reversal of 21122211010231 is 13201011222112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21122211010231 - 211 = 21122211008183 is a prime.
It is a super-2 number, since 2×211222110102312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21122211010199 and 21122211010208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21122211010237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561105505115 + 10561105505116.
It is an arithmetic number, because the mean of its divisors is an integer number (10561105505116).
Almost surely, 221122211010231 is an apocalyptic number.
21122211010231 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122211010231 is an equidigital number, since it uses as much as digits as its factorization.
21122211010231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 21122211010231 its reverse (13201011222112), we get a palindrome (34323222232343).
The spelling of 21122211010231 in words is "twenty-one trillion, one hundred twenty-two billion, two hundred eleven million, ten thousand, two hundred thirty-one".
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