Base | Representation |
---|---|
bin | 110000000001101100000001… |
… | …011101101100101000101011 |
3 | 1000200212122110202200221221121 |
4 | 300001230001131230220223 |
5 | 210141131102112242303 |
6 | 2025122052052520111 |
7 | 62330205355606315 |
oct | 6001540135545053 |
9 | 1020778422627847 |
10 | 211222221212203 |
11 | 61335928360043 |
12 | 1b834346620037 |
13 | 90b2229627476 |
14 | 3a232d25627b5 |
15 | 19645949459bd |
hex | c01b0176ca2b |
211222221212203 has 2 divisors, whose sum is σ = 211222221212204. Its totient is φ = 211222221212202.
The previous prime is 211222221212137. The next prime is 211222221212243. The reversal of 211222221212203 is 302212122222112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211222221212203 is a prime.
It is a super-2 number, since 2×2112222212122032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211222221212243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611110606101 + 105611110606102.
It is an arithmetic number, because the mean of its divisors is an integer number (105611110606102).
Almost surely, 2211222221212203 is an apocalyptic number.
211222221212203 is a deficient number, since it is larger than the sum of its proper divisors (1).
211222221212203 is an equidigital number, since it uses as much as digits as its factorization.
211222221212203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 211222221212203 its reverse (302212122222112), we get a palindrome (513434343434315).
The spelling of 211222221212203 in words is "two hundred eleven trillion, two hundred twenty-two billion, two hundred twenty-one million, two hundred twelve thousand, two hundred three".
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