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21122343133 is a prime number
BaseRepresentation
bin10011101010111111…
…010110000011011101
32000112001102012120221
4103222333112003131
5321224304440013
613411541041341
71345300645213
oct235277260335
960461365527
1021122343133
118a5a015031
1241159b6251
131cb807c3b8
14104539ccb3
1583956708d
hex4eafd60dd

21122343133 has 2 divisors, whose sum is σ = 21122343134. Its totient is φ = 21122343132.

The previous prime is 21122343113. The next prime is 21122343157. The reversal of 21122343133 is 33134322112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20541195684 + 581147449 = 143322^2 + 24107^2 .

It is a cyclic number.

It is not a de Polignac number, because 21122343133 - 221 = 21120245981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21122343098 and 21122343107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21122343113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561171566 + 10561171567.

It is an arithmetic number, because the mean of its divisors is an integer number (10561171567).

Almost surely, 221122343133 is an apocalyptic number.

It is an amenable number.

21122343133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21122343133 is an equidigital number, since it uses as much as digits as its factorization.

21122343133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 25.

Adding to 21122343133 its reverse (33134322112), we get a palindrome (54256665245).

The spelling of 21122343133 in words is "twenty-one billion, one hundred twenty-two million, three hundred forty-three thousand, one hundred thirty-three".