Base | Representation |
---|---|
bin | 10011101010111111… |
… | …100110011010100011 |
3 | 2000112001112121111221 |
4 | 103222333212122203 |
5 | 321224314111042 |
6 | 13411542315511 |
7 | 1345301344456 |
oct | 235277463243 |
9 | 60461477457 |
10 | 21122410147 |
11 | 8a5a060413 |
12 | 4115a28b97 |
13 | 1cb80a3a57 |
14 | 10453b949d |
15 | 83957bd67 |
hex | 4eafe66a3 |
21122410147 has 2 divisors, whose sum is σ = 21122410148. Its totient is φ = 21122410146.
The previous prime is 21122410103. The next prime is 21122410229. The reversal of 21122410147 is 74101422112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21122410147 is a prime.
It is not a weakly prime, because it can be changed into another prime (21122410247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561205073 + 10561205074.
It is an arithmetic number, because the mean of its divisors is an integer number (10561205074).
Almost surely, 221122410147 is an apocalyptic number.
21122410147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122410147 is an equidigital number, since it uses as much as digits as its factorization.
21122410147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 21122410147 its reverse (74101422112), we get a palindrome (95223832259).
The spelling of 21122410147 in words is "twenty-one billion, one hundred twenty-two million, four hundred ten thousand, one hundred forty-seven".
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