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21123301312229 is a prime number
BaseRepresentation
bin1001100110110001001101…
…10111110000011011100101
32202210100221012001120122112
410303120212313300123211
510232041010113442404
6112531524411410405
74310052045442214
oct463304667603345
982710835046575
1021123301312229
1168043839a8866
122451a06a53a05
13ba2bc36b830c
1453053224907b
152696eb31456e
hex133626df06e5

21123301312229 has 2 divisors, whose sum is σ = 21123301312230. Its totient is φ = 21123301312228.

The previous prime is 21123301312219. The next prime is 21123301312247. The reversal of 21123301312229 is 92221310332112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12785616187204 + 8337685125025 = 3575698^2 + 2887505^2 .

It is a cyclic number.

It is not a de Polignac number, because 21123301312229 - 236 = 21054581835493 is a prime.

It is a super-3 number, since 3×211233013122293 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21123301312195 and 21123301312204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21123301312219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561650656114 + 10561650656115.

It is an arithmetic number, because the mean of its divisors is an integer number (10561650656115).

Almost surely, 221123301312229 is an apocalyptic number.

It is an amenable number.

21123301312229 is a deficient number, since it is larger than the sum of its proper divisors (1).

21123301312229 is an equidigital number, since it uses as much as digits as its factorization.

21123301312229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 21123301312229 in words is "twenty-one trillion, one hundred twenty-three billion, three hundred one million, three hundred twelve thousand, two hundred twenty-nine".