Base | Representation |
---|---|
bin | 1001100110110010100100… |
… | …11001011001111000011010 |
3 | 2202210102211002010122201212 |
4 | 10303121102121121320122 |
5 | 10232044004034144200 |
6 | 112532125055143122 |
7 | 4310106123414206 |
oct | 463312231317032 |
9 | 82712732118655 |
10 | 21124031553050 |
11 | 6804719122578 |
12 | 2451b8b514aa2 |
13 | ba2caba8518a |
14 | 5305a1215b06 |
15 | 2697404ac035 |
hex | 133652659e1a |
21124031553050 has 12 divisors (see below), whose sum is σ = 39290698688766. Its totient is φ = 8449612621200.
The previous prime is 21124031553041. The next prime is 21124031553101. The reversal of 21124031553050 is 5035513042112.
It can be written as a sum of positive squares in 3 ways, for example, as 19136503971841 + 1987527581209 = 4374529^2 + 1409797^2 .
It is a junction number, because it is equal to n+sod(n) for n = 21124031552998 and 21124031553016.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 211240315481 + ... + 211240315580.
Almost surely, 221124031553050 is an apocalyptic number.
21124031553050 is a deficient number, since it is larger than the sum of its proper divisors (18166667135716).
21124031553050 is a wasteful number, since it uses less digits than its factorization.
21124031553050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422480631073 (or 422480631068 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 21124031553050 its reverse (5035513042112), we get a palindrome (26159544595162).
The spelling of 21124031553050 in words is "twenty-one trillion, one hundred twenty-four billion, thirty-one million, five hundred fifty-three thousand, fifty".
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